Kanjani ukubala ububanzi we mbuthano?

Okokuqala, ake sibone ukuthi yini embuthanweni futhi ihluke kanjani kusuka embuthanweni. Thatha usiba noma ipensela nopende obomvu ephepheni umbuthano njalo. Penda lonke phakathi sibalo okuholela blue ipensela. Red uhlaka olukhombisa emngceleni ukuma - umbuthano. Kodwa okuqukethwe okwesibhakabhaka ngaphakathi - futhi kukhona umbuthano.

Ubukhulu kwendilinga kanye ubukhulu umbuthano kunqunywa. Emgqeni obomvu wokugubha embuthanweni, ukumaka amaphuzu amabili kangangokuthi babengakwazi esibukweni izithombe nomunye. Matanisa kubo umugqa. Ingxenye ngizodabula iphuzu esikhungweni umbuthano. Lokhu ingxenye yokuxhuma izingxenye eziphikisanayo umbuthano, futhi ibizwa ngokuthi i-geometry ubukhulu.

Ingxenye eyehlayo hhayi ngokusebenzisa maphakathi mbuthano, kodwa okuhlanganisiwe ne-semikhawulweni okuphambene libizwa kuzithinta. Ngenxa yalokho, kuzithinta ligijima iphuzu maphakathi umbuthano, futhi ubukhulu bayo kuyinto.

ubukhulu okhonjiswe Latin incwadi D. Ukuthola ububanzi we umbuthano kungaba yamanani ezifana ndawo, ubude engaba umbuthano.

Ibanga kusukela iphuzu sosizo ukuze iphuzu selilonke imisiwe, ngokuthi engaba futhi kuboniswa incwadi R. Ukumazi engaba ubukhulu umbuthano kusiza ukubala isenzo esilula:

D = 2 * R

. Ngokwesibonelo, engaba - 7 cm 7 cm nande by 2 futhi ukuthola elilingana 14 cm A: D ilingana sibalo kusengaphambili 14 cm ..

Ngesinye isikhathi kuyadingeka ukunquma ubukhulu wombuthano kanye ubude bayo. Lapha kubalulekile ukusebenzisa ifomula ekhethekile esisiza ukunquma selilonke. Isibalo 2 L = Pi * R, lapho 2 - kuyinto ukubaluleka njalo (njalo), futhi Pi = 3.14. Futhi njengoba kwaziwa ukuthi R eyaziwa = D * 2, bese ifomula kungenziwa amelwe ngenye indlela

L = Pi * D

D = L / Pi

Le nkulumo osebenza ububanzi ifomula mbuthano. Uma kufakwa ukubaluleka owaziwayo izimo zokuxazulula izinkinga azenzeki i equation nomunye engaziwa. Lokucabanga Ubude 7 m Ngenxa yalokho .:

D = 7/3, 14

D = 21, 98

A: ububanzi 21,98 amamitha.

Uma ukubaluleka kwendawo yaziwa, kungenzeka ukunquma ububanzi we umbuthano. Ifomula ukuthi isetshenziswa Kulokhu simiswe ngalendlela lelandzelako:

D = 2 * (S / PI) * (1/2)

S - kulokhu endaweni sibalo. Ngokwesibonelo, e umsebenzi ke uyalingana 30 square metres. M. Sithola:

D = 2 * (30/3, 14) * (1/2) D = 9 55414

Lapho umsebenzi ojutshiwe ezidlula elilingana ivolumu (V) ibhola, le ndlela elandelayo ithola ubukhulu: D = (6 V / PI) * 1/3.

Ngezinye izikhathi kufanele uthole ububanzi umbuthano alotshiwe unxantathu. Ngenxa yale njongo, ngokuvumelana ifomula emelelwa lokuthola umbuthano engaba:

R = S / p (S - endaweni kusengaphambili unxantathu, futhi p - ipherimitha ehlukaniswa 2).

Umphumela ngokuphindwe kabili, ucabangela ukuthi D = 2 * R.

Ngokuvamile ukuthola ubukhulu kumbuthano futhi babe ekhaya. Ngokwesibonelo, uma izama Usayizi indandatho, okulingana ubukhulu bayo. Ukuze wenze lokhu, bopha ngomunwe umnikazi ezingaba ngentambo indandatho. Dwebela amaphuzu lokuxhumana imikhawulo ezimbili. Kala ubude umugqa kusukela iphuzu ukuze ukhombe. Inani okuholela iyanda yi 3.14, kulandela ifomula sokunquma ububanzi nobude ezaziwayo. Ngakho, isitatimende ukuthi ulwazi geometry ne-Aljibhra empilweni akusizi, musa njalo zivumelana ngokoqobo. Futhi isizathu sina ukuthatha imithwalo yemfanelo ethe xaxa ngoba izifundo esikoleni.